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### GATE Question of The Day - Digital Electronics Questions

Hi dear GATE aspirants! I am SouravMani.From today we are going to discuss Digital Electronics Questions on daily basis. hope you all co-operate and making use of it.

The logic functions implemented by the circuit below is (Ground implies a logic "0")

A) F = AND(P,Q)
B) F = OR(P,Q)
C) F = XNOR(P,Q)
D) F = XOR(P,Q)

I kindly requesting of the GATE aspirants to justify yours valuable Answers.

Unknown said...

D is the ans

Anonymous said...

Can you please justify above..

Vamshi said...

haah... its D for sure.... good question dude... but a little bit easy right...

Examsavvy said...

ya people are asking easy question also, but you dont worry we have some very tough question for you. he he

Unknown said...

option D

Vamshi said...

hoh man... i didn't mean that...actually every one can solve easy questions right if they know the concepts perfectly... but i am telling you that whether the question is easy or tough but it should be some what tricky and thinkable dude...i am telling you that only...

Examsavvy said...

hmm ok

Examsavvy said...

vamshi here i left some of the part for you http://www.gate.examsavvy.com/2012/08/gate-question-of-day-general-aptitude_30.html

Unknown said...

D
damn easy.. :)
but stil a gud one..

SouravMani said...

Dont worry dude's always begin with a easy ones from which you get confidence to go ahead!

Vamshi said...

hmm gud suggestion dude...

Unknown said...

D is the answer

SouravMani said...

Off course many aspirants have done their suggestions/justifications well. yes guys you are obsolutely correct! The answer is option D. well done friends*

Unknown said...

option D
I0 fed with logic 0
I1 fed with logic 1
I2 fed with logic 1
I3 fed with logic 0
Hence in order to select I1 or I2 we can have combinations either Q=0 P=1 for I1 and Q=1 P=0 for I2. So we can represent this easily by XOR between P and Q. Hence F=XOR(P,Q). :)

Barnali said...

damn easy....:P

peehu jain said...

D is d ans.